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Message from discussion A tricky ODE
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alainverghote@gmail.com  
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 More options Nov 7 2009, 1:00 pm
Newsgroups: sci.math
From: "alainvergh...@gmail.com" <alainvergh...@gmail.com>
Date: Sat, 7 Nov 2009 05:00:21 -0800 (PST)
Local: Sat, Nov 7 2009 1:00 pm
Subject: Re: A tricky ODE
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On 7 nov, 09:57, Patrick Coilland <pcoill...@pcc.fr> wrote:

> daniel D a écrit :

> > Hi,

> > I came across the following differential equation:

> > sqrt(1+(y')^2)=(d/dx)((yy')/sqrt(1+(y')^2))

> > I found a possible solutions: y(x)=cosh(x+C1).
> > However, this is a second order ODE so there exist a more general solution, with 2 freedom degrees.

> > Can anyone find it?

> (cosh(ax+b))/a

Dear Friends,

Without solving it
does it exist a  way to give the parity of the solutions y(x)?

Alain


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