> > < The proposed experiment is designed to detect the absolute
> motion of earth through measurement of tiny differences in up-link
> and down-link signal propagation times between two fixed points A
> and B,but without relying on the wave properties of light. >

>   Let light be a disturbance moving at c through a local space taken
> as stationary.  Let A and B be two points 1 unit apart on the Y axis
> of system K that is moving through this space at .6c in the x
> direction. At t = 0 let a ray of light emit from A toward B and
> reflect therefrom back to A.
>   As plotted by a system k' at rest in this space, with its X' axis
> coinciding with X of K and its vertical axes parallel to those of K,
> the ray moves up Y at c' = qc, where q = sqrt of (1 - v^2/c^2), thus
> takes t' = 1.25 seconds each way. In order for K to measure this as 1
> secodn each way, thus to let c' = 1 as plotted by K, clocks of the
> moving system have to run slow by q, wherefore t = qt = .8 x 1.2 each
> way. (Note that the path of the beam is on the hypotenuse of a right
> triangle, of which Y is one side and vc is the length of the other.
> given that B is 1 unit from A on Y, then AB = 1 is the length of Y as
> measured by both systems; and the hypotenuse is 1.2 units long as
> measured by k; which is WHY ittakes a ray 1.25 seconds to get from A
> to b as plotted by stationary cs k.
>   HOWEVER!!  There is no reason to let moving systems clocks run slow
> by q or for their vertical axes to remain undeformed while their
> horizontal axis shrinks by q. Suppose, for instance, that lengths
> remain constant in the direction a system is moving through the above
> stationary space. If its lengths EXPAND by 1/q in the vertical axes
> and its clocks run slow by q = q^2 = (c^2-v^2), then it would measure
> the light's time from A to B and from B to A, thus up and then down Y
> or Z as t = 1 second, and the speed of light would remain c = 1 unit/
> sec as plotted by K.
>   Suppose that lengths in the vertical axes SHRINK by q. then clocks
> of moving systems could keep identical rates as stationary ones and it
> would still take 1 second for a ray to travel up 1 unit on y and back
> again. (If that happens, then lengths in the direction of motion would
> have to shrink by Q in order to measure the round-trip time as 1
> second per unit of length, thus for c to remain equal to 1 as plotted
> by the moving systems. As to the one way times per unit length of such
> deformed systems, unless clocks of each such system is set to MEASURE
> c = 1 in all directions - i.e. to be esynched via Einstein's defined
> method which he called "synchronized" - they won't.)

> p.s.  If we let moving systems deform as per the LTE - thus let
> lengths remain constant in the vertical axes and shrink by q in the
> direction of motion, with clocks running q slow - and consider the
> first case discused above, then even though rays would travel up and
> down Y in 1 second each way as plottted by k, the ray would have
> emitted from x=y=x'=y'=0 and would return to x=y=y'=0 as plotted by k
> and k; but would NOT have returned to x' = 0 as plotted by the
> stationary system k! It would return to x' = 0 + 2vt'; which is WHY
> the moving clocks on X have to have a Voigtian local time offset of -
> vx/c^2 seconds per successive clock, in which x is the distance
> between two such clocks as measured by the given moving system itself,
> and v - which doesn't have to be known by the esyching cs - is its
> speed in the 'empty space" in which Einstein postulated that light
> moves at c.

> glird