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Newsgroups: sci.math
From: Patrick Coilland <pcoill...@pcc.fr>
Date: Sat, 07 Nov 2009 09:57:56 +0100
Local: Sat, Nov 7 2009 8:57 am
Subject: Re: A tricky ODE
daniel D a écrit :
> Hi, (cosh(ax+b))/a > I came across the following differential equation: > sqrt(1+(y')^2)=(d/dx)((yy')/sqrt(1+(y')^2)) > I found a possible solutions: y(x)=cosh(x+C1). > Can anyone find it? You must Sign in before you can post messages.
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