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Newsgroups: sci.math
From: Pubkeybreaker <pubkeybrea...@aol.com>
Date: Wed, 4 Nov 2009 13:01:09 -0800 (PST)
Local: Wed, Nov 4 2009 9:01 pm
Subject: Re: finding volume of a torus
On Nov 4, 11:43 am, aegis <ae...@mad.scientist.com> wrote:
> I have the circle (x-1)^2 + y^2 = 1 and I'm rotating it Thm: > around the y-axis. > dV = 2*pi*x * h(x) dx > where h(x) = 2*sqrt(1 - (x - 1)^2 ) > integrating from 0 to 2, I end up with The volume will equal the cross-sectional area times the distance travelled by the centroid of the cross section as you rotate it. You must Sign in before you can post messages.
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