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Newsgroups: sci.math
From: Bacle <ba...@yahoo.com>
Date: Tue, 03 Nov 2009 15:54:29 EST
Local: Tues, Nov 3 2009 8:54 pm
Subject: Re: N^2-(N-1)^2== Infinite prime number series, please check this out
I think you mean :
n^n -(n-1)^(n-1) is always prime. This is false: 6^6-5^5 =43531=101*431 If you mean N^2-(N-1)^2 is always prime , this is false too: N^2-(N-1)^2 =2N-1 . Use, e.g, N=8 . Then 2N-1=15. You must Sign in before you can post messages.
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