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eigenvalues of A
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G Patel  
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 More options Nov 5 2009, 2:56 am
Newsgroups: sci.math
From: G Patel <gaya.pa...@gmail.com>
Date: Wed, 4 Nov 2009 18:56:01 -0800 (PST)
Local: Thurs, Nov 5 2009 2:56 am
Subject: eigenvalues of A
true or false.... eigenvalues of A are same as eigenvalues of kA
(because if v is eigenvector for A, then kv is eigenvector for kA)

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Arturo Magidin  
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 More options Nov 5 2009, 3:06 am
Newsgroups: sci.math
From: Arturo Magidin <magi...@member.ams.org>
Date: Wed, 4 Nov 2009 19:06:40 -0800 (PST)
Local: Thurs, Nov 5 2009 3:06 am
Subject: Re: eigenvalues of A
On Nov 4, 8:56 pm, G Patel <gaya.pa...@gmail.com> wrote:

> true or false.... eigenvalues of A are same as eigenvalues of kA
> (because if v is eigenvector for A, then kv is eigenvector for kA)

What is k, a scalar?

If so, then:

   (i) What are the eigenvalues of a diagonal matrix?
  (ii) If A is a diagonal matrix, what is kA?
 (iii) What are the eigenvalues of kA, then?

If k is not a scalar, then what is it?

--
Arturo Magidin


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Gerry Myerson  
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 More options Nov 5 2009, 3:09 am
Newsgroups: sci.math
From: Gerry Myerson <ge...@maths.mq.edi.ai.i2u4email>
Date: Thu, 05 Nov 2009 14:09:20 +1100
Local: Thurs, Nov 5 2009 3:09 am
Subject: Re: eigenvalues of A
In article
<5da73f76-99b2-455e-8788-0034cc6d9...@t2g2000yqn.googlegroups.com>,
 G Patel <gaya.pa...@gmail.com> wrote:

> true or false.... eigenvalues of A are same as eigenvalues of kA

true if k = 1 and in some other fairly trivial cases, false most of
the time. If I is the identity matrix, are the eigenvalues of I
the same as the eigenvalues of 2I?

> (because if v is eigenvector for A, then kv is eigenvector for kA)

I'm not familiar with this use of the word, "because."

--
Gerry Myerson (ge...@maths.mq.edi.ai) (i -> u for email)


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G Patel  
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 More options Nov 5 2009, 3:48 am
Newsgroups: sci.math
From: G Patel <gaya.pa...@gmail.com>
Date: Wed, 4 Nov 2009 19:48:07 -0800 (PST)
Local: Thurs, Nov 5 2009 3:48 am
Subject: Re: eigenvalues of A
On Nov 4, 9:56 pm, G Patel <gaya.pa...@gmail.com> wrote:

> true or false.... eigenvalues of A are same as eigenvalues of kA
> (because if v is eigenvector for A, then kv is eigenvector for kA)

if c is eigenvalue of A, then Ax = cx for nonzero x, multiply both
sides by nonzero scalar k: (kA)x = c(kx) , thus c is also eigenvalue
of kA?

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Arturo Magidin  
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 More options Nov 5 2009, 4:25 am
Newsgroups: sci.math
From: Arturo Magidin <magi...@member.ams.org>
Date: Wed, 4 Nov 2009 20:25:25 -0800 (PST)
Local: Thurs, Nov 5 2009 4:25 am
Subject: Re: eigenvalues of A
On Nov 4, 9:48 pm, G Patel <gaya.pa...@gmail.com> wrote:

> On Nov 4, 9:56 pm, G Patel <gaya.pa...@gmail.com> wrote:

> > true or false.... eigenvalues of A are same as eigenvalues of kA
> > (because if v is eigenvector for A, then kv is eigenvector for kA)

> if c is eigenvalue of A, then Ax = cx for nonzero x, multiply both
> sides by nonzero scalar k: (kA)x = c(kx) , thus c is also eigenvalue
> of kA?

An eigenvalue of A is a scalar c such that there exists a nonzero
vector x for which Ax=cx.

Note that the vector on the left side of "Ax=cx" is the *same* as the
vector on the right side of "Ax=cx".

Question: is the vector on the left side of your "(kA)x = c(kx)" the
same as the vector on your right hand side?

And to put it even more plainly, *again*:

What are the eigenvalues of, say, the identity matrix?

What are the eigenvalues of k times the identity?

PS: You are utterly confused; go talk to your professor because you
are just not getting this.

--
Arturo Magidin


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