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Difference between R^n and Euclidean n-space?
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Bacle  
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 More options Nov 7, 2:02 am
Newsgroups: sci.math
From: Bacle <ba...@yahoo.com>
Date: Fri, 06 Nov 2009 21:02:52 EST
Local: Sat, Nov 7 2009 2:02 am
Subject: Difference between R^n and Euclidean n-space?
Hi, everyone:

   I have seen authors like John Lee in his "Smooth Manifolds" book, use these two terms as being different, but without , AFAIK, explaining the difference between the two.

  I assume it may be that Euclidean n-space is the manifold R^n with a preferred , or "default" chart, but I am not sure of this.

  Anyone Else Know.?.

  Thanks In Advance.


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Discussion subject changed to "Bacle is gay." by debaser
debaser  
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 More options Nov 7, 3:27 am
Newsgroups: sci.math
From: debaser <marty.musa...@gmail.com>
Date: Fri, 6 Nov 2009 19:27:03 -0800 (PST)
Local: Sat, Nov 7 2009 3:27 am
Subject: Bacle is gay.
Say-Hey-Mistert-gay+guy-girl+start
+gayodemayomegalphatronicstoplutoniumbrellandpeanutbutterandjelly


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Discussion subject changed to "Difference between R^n and Euclidean n-space?" by G. A. Edgar
G. A. Edgar  
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 More options Nov 7, 10:56 am
Newsgroups: sci.math
From: "G. A. Edgar" <ed...@math.ohio-state.edu.invalid>
Date: Sat, 07 Nov 2009 05:56:16 -0500
Local: Sat, Nov 7 2009 10:56 am
Subject: Re: Difference between R^n and Euclidean n-space?
In article
<808290445.28584.1257559402748.JavaMail.r...@gallium.mathforum.org>,

Bacle <ba...@yahoo.com> wrote:
> Hi, everyone:

>    I have seen authors like John Lee in his "Smooth Manifolds" book, use
> these two terms as being different, but without , AFAIK, explaining the
> difference between the two.

>   I assume it may be that Euclidean n-space is the manifold R^n with a
> preferred , or "default" chart, but I am not sure of this.

>   Anyone Else Know.?.

>   Thanks In Advance.

I would probably say that R^n is Euclidean n-space together with a
coodinate system.  Euclidean n-space has no preferred point "the
origin" nor preferred directions for the coordinate planes, while R^n
has all of those.

--
G. A. Edgar                              http://www.math.ohio-state.edu/~edgar/


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master1729  
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 More options Nov 7, 12:07 pm
Newsgroups: sci.math
From: master1729 <tommy1...@gmail.com>
Date: Sat, 07 Nov 2009 07:07:17 EST
Local: Sat, Nov 7 2009 12:07 pm
Subject: Re: Difference between R^n and Euclidean n-space?
G.A. Edgar wrote :

indeed.

tommy1729


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Richard L. Peterson  
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 More options Nov 9, 5:30 am
Newsgroups: sci.math
From: "Richard L. Peterson" <rl_p...@yahoo.com>
Date: Mon, 09 Nov 2009 00:30:56 EST
Local: Mon, Nov 9 2009 5:30 am
Subject: Re: Difference between R^n and Euclidean n-space?

So is Euclidean n-space what's referred to
by "affine" space? Thanks, Rich Peterson

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adamk  
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 More options Nov 9, 6:09 am
Newsgroups: sci.math
From: adamk <ad...@adamk.net>
Date: Mon, 09 Nov 2009 01:09:16 EST
Local: Mon, Nov 9 2009 6:09 am
Subject: Re: Difference between R^n and Euclidean n-space?
I thought R^n was a model for the axioms of Euclidean
 n-dimensional geometry, maybe a particular model.

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Zdislav V. Kovarik  
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 More options Nov 9, 2:46 pm
Newsgroups: sci.math
From: "Zdislav V. Kovarik" <kova...@mcmaster.ca>
Date: Mon, 9 Nov 2009 09:46:54 -0500
Local: Mon, Nov 9 2009 2:46 pm
Subject: Re: Difference between R^n and Euclidean n-space?

An affine space does not have a metric structure (yet). One can play
around with setting up axioms for the metric, without specifying the
origin or axes. A "preferred" metric satisfying the Parallelogram Law will
do. (It is a classical exercise how to obtain the inner product in the
underlying vector space out of it by polarization -- then you can measure
angles etc.) But under merely affine transformations, angles get
distorted.

Cheers, ZVK(Slavek).


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G. A. Edgar  
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 More options Nov 9, 6:12 pm
Newsgroups: sci.math
From: "G. A. Edgar" <ed...@math.ohio-state.edu.invalid>
Date: Mon, 09 Nov 2009 13:12:35 -0500
Local: Mon, Nov 9 2009 6:12 pm
Subject: Re: Difference between R^n and Euclidean n-space?

> An affine space does not have a metric structure (yet). One can play
> around with setting up axioms for the metric, without specifying the
> origin or axes. A "preferred" metric satisfying the Parallelogram Law will
> do. (It is a classical exercise how to obtain the inner product in the
> underlying vector space out of it by polarization -- then you can measure
> angles etc.) But under merely affine transformations, angles get
> distorted.

> Cheers, ZVK(Slavek).

Agreed.  Euclidean space has congruence, but affine space doesn't.

--
G. A. Edgar                              http://www.math.ohio-state.edu/~edgar/


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Discussion subject changed to "Bacle is gay." by master1729
master1729  
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 More options Nov 9, 10:35 pm
Newsgroups: sci.math
From: master1729 <tommy1...@gmail.com>
Date: Mon, 09 Nov 2009 17:35:16 EST
Local: Mon, Nov 9 2009 10:35 pm
Subject: Re: Bacle is gay.
'guest' wrote :

ok , mr ' guest ' , we are on to you.

we know that usually when ' guest ' replies with complete nonsense its probably -> MUSATOV.

dear musatov , God knows about your sins ; your insults under the name of ' guest '.

unless masatov believes in a god more retarded than himself.

but that is of course not possible , the creator of the universe - if he even exists - could not possibly be more retarded than musatov , otherwise he would not be able to create.

for this sin musatov will go to hell.

regards

tommy1729


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Discussion subject changed to "musatov is gay, a thief liar and cheat.." by Bacle
Bacle  
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 More options Nov 9, 11:30 pm
Newsgroups: sci.math
From: Bacle <ba...@yahoo.com>
Date: Mon, 09 Nov 2009 18:30:49 EST
Local: Mon, Nov 9 2009 11:30 pm
Subject: Re: musatov is gay, a thief liar and cheat..
And cheated his way thru his whole life.

  Notice how musatov never responded to specific
 accusations I made.


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master1729  
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 More options Nov 10, 8:46 pm
Newsgroups: sci.math
From: master1729 <tommy1...@gmail.com>
Date: Tue, 10 Nov 2009 15:46:57 EST
Local: Tues, Nov 10 2009 8:46 pm
Subject: Re: musatov is gay, a thief liar and cheat..
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